(2m+20)^2+(3m)^2=(5m)^2

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Solution for (2m+20)^2+(3m)^2=(5m)^2 equation: 



(2m+20)^2+(3m)^2=(5m)^2

We move all terms to the left:

(2m+20)^2+(3m)^2-((5m)^2)=0

determiningTheFunctionDomain
3m^2+(2m+20)^2-5m^2=0

We add all the numbers together, and all the variables

3m^2-5m^2+(2m+20)^2=0

We add all the numbers together, and all the variables

-2m^2+(2m+20)^2=0

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